11.21 Posted In Soal Fisika Edit This 0 Comments »
1. t=5 dt ; s = 1,7 km = 1700 m
2. t = 2 dt ; v = 1.500 m/dt
3. s = 1,7 km= 1.700 m ; Δt = 3,87 dt ; v di udara = 340 m/dt
4. t = 6 dt ; v = 340 m/dt
5. t = 4 dt ; v = 340 m/dt
6. t = 0,5 dt ; v = 1.500 m/dt
7. a : e = 40 : 30
8. f1 = 330 Hz ==>> f2 ( 2 oktaf lebih tinggi)
9. l = 20 cm = 0,2 m ; f = 425 Hz
10. a. f = 500 Hz ; l = 17 cm= 0,17 m
v = s/t = 1700 m /5 dt = 340 m/dt
2. t = 2 dt ; v = 1.500 m/dt
s = v x t = 1.500 m/dt x 2 dt = 3000 m =3 km
3. s = 1,7 km= 1.700 m ; Δt = 3,87 dt ; v di udara = 340 m/dt
t di udara = s/v = 1.700 m/340 m/dt = 5 dt
t di air = 5 dt - 3,87 dt = 1,13 dt
v di air = s/t = 1.700 m/1,13 dt = 1504,42 m/dt
4. t = 6 dt ; v = 340 m/dt
= (v x t)/2 = ( 340 x 6 )/2 = 1020 meter
5. t = 4 dt ; v = 340 m/dt
s = v x t = 340 m/dt x 4 dt = 1.360 m
6. t = 0,5 dt ; v = 1.500 m/dt
s = ( v x t )/2 = (1.500 x 0,5 ) / 2 = 375 meter
7. a : e = 40 : 30
a : e = 40 : 30 ==>> 440 : e = 40 : 30 ==>> e = (440x30)/40 = 330 Hz
8. f1 = 330 Hz ==>> f2 ( 2 oktaf lebih tinggi)
f1 : f2 = 1 : 4 ==>> 330 : f2 = 1 : 4 ==>> f2 = 330 x 4 = 1.320 Hz
f2 (1 oktaf lebih rendah)
f1 : f2 = 1 : 1/2 ==>> 330 : f2 = 1 : 1/2 ==>> f2 = 330 x 1/2 = 165 Hz
9. l = 20 cm = 0,2 m ; f = 425 Hz
λ = l x 4 = 0,2 x 4 = 0,8 m ==>> v = λ x f = 0,8 x 425 = 340 m/dt
10. a. f = 500 Hz ; l = 17 cm= 0,17 m
λ = l x 4 = 0,17 x 4 = 0,68 m ==>> v = λ x f = 0,68 x 500 = 340 m/dt
b. f = 400 Hz ==>> λ = v / f = 340 / 400 = 0,85 m ==>> l = 1/4 x λ = 1/4 x 0,85 = 0,2125 m

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